Answer:
Option A
Explanation:
According to question, force acting on the particle inside the magnetic field is given by
FB=qvBsinθ
[where θ= angle between v and B]
This force FB provides necessary centripetal force for circular motion of the charged particle.
So, mv2r=qvBsinθ
Now, for particles x and y and θ = 90°
mxv2xr1=qvxB...................(i)
myv2yr2=qvyB...........(ii)
From Eqs.(i) and (ii) , we get
mxvxmyvy=r1r2
as, vxvy=1
So, mxmy=r1r2