Discussion Forum

A iron rod is placed parallel to the magnetic field of intensity 2000 Am^-1. The magnetic flux through the rod is $6 \times 10^{-4} Wb$ and its cross-sectional area is 3 cm² . The magnetic permeability  of the  rod in Wb A^-1m^-1 is 

Answer:

Explanation:

According to question  , magnetic

permeability of the rod is given by , $\mu_{r}=\frac{B}{B_{0}}$

where, B= magnetic field without iron rod

B₀ = magnetic field after insertion of iron  rod

so,  $\mu_{r}=\frac{B}{2000Am^{-1}}$

 $\left( \because B.A=\phi\Rightarrow B=\frac{\phi}{A}=\frac{6 \times 10 ^{-4}Wb}{3\times 10^{-4}m^{2}}=2 Wbm^{-2}\right)$

 So,   $\mu_{r}=\frac{2}{2000}=10^{-3}$