1)

The degree and order of the differential equation 

[1+(dydx)3]7/3=7(d2ydx2) respectively are


A) 3 and 7

B) 3 and 2

C) 7 and 3

D) 2 and 3

Answer:

Option B

Explanation:

Given , differential equation  is 

[1+(dydx)]7/3=7(d2ydx2)

 On cubing both sides, we get

[1+(dydx)3]7=73(d2ydx2)3

Here, we see that highest  order derivative is 2, whose degree is 3.

 Hence , degree =3 and order=2