1) The degree and order of the differential equation [1+(dydx)3]7/3=7(d2ydx2) respectively are A) 3 and 7 B) 3 and 2 C) 7 and 3 D) 2 and 3 Answer: Option BExplanation:Given , differential equation is [1+(dydx)]7/3=7(d2ydx2) On cubing both sides, we get [1+(dydx)3]7=73(d2ydx2)3 Here, we see that highest order derivative is 2, whose degree is 3. Hence , degree =3 and order=2