1)

  Direction  cosines of the line  $\frac{x+2}{2}=\frac{2y-5}{3}=z$  =-1 are 


A) $\frac{4}{5}, \frac{3}{5}$,0

B) $\frac{3}{5}, \frac{4}{5},\frac{1}{5}$

C) $-\frac{3}{5}, \frac{5}{5}$,0

D) $\frac{4}{5}, -\frac{2}{5},\frac{1}{5}$

Answer:

Option A

Explanation:

 Given equation of line is,

 $\frac{x+2}{2}=\frac{2y-5}{3}, z+1=0$

or   $\frac{x+2}{2}=\frac{y-\frac{5}{2}}{\frac{3}{2}},z+1=0$

 Hence, DR of a line are $<2 , \frac{3}{2} ,0 >$

Now,   $\sqrt{2^{2}+\left(\frac{3}{2}\right)^{2}+0}=\sqrt{4+\frac {9}{4}}=\sqrt{\frac{25}{4}}=\frac{5}{2}$

 $\therefore$    DC of a line are   $< \frac{2}{5/2}, \frac{3/2}{5/2},0 > or < \frac{4}{5},\frac{3}{5},0>$