Answer:
Option A
Explanation:
For first order reaction, $k=\frac{2.303}{t}\log\frac{[A_{0}]}{[A]}$
At $t= t_{1/2}$,[A]=$[A_{0}]$/2
$k=\frac{2.303}{t_{1/2}}\log\frac{[A_{}]}{[A_{0}]/2};k=\frac{2.303}{t_{1/2}}\log 2$
$k=\frac{2.303}{t_{1/2}} $ or $t_{1/2}=\frac{0.693}{k}$