1) The reaction takes place in two steps as (i) $ NO_{2}Cl(g) $ $\underrightarrow{k_{1}}$ $ NO_{2}(g)+Cl(g)$ (ii) $NO_{2}Cl(g)+Cl(g)$ $\underrightarrow{k_{2}}$ $ NO_{2}(g)+Cl(g)$ Identify the reacttion intermediate. A) $NO_{2}Cl(g)$ B) $NO_{2}$ C) $Cl_{2}$ D) Cl(g) Answer: Option DExplanation: Cl(g) is the reaction intermediate involved in the formation of $NO_{2}$ (g) and $Cl_{2}$ (g). Reaction intermediates are those which are formed within the reaction and has no presence in the products. Cl(g) is involved in both the reactions $ NO_{2}Cl(g) $ $\underrightarrow{k_{1}}$ $ NO_{2}(g)+Cl(g)$ $NO_{2}Cl(g)+Cl(g)$ $\underrightarrow{k_{2}}$ $ NO_{2}(g)+Cl(g)$