1)

 The reaction  takes place in two steps as

(i)    $ NO_{2}Cl(g) $   $\underrightarrow{k_{1}}$   $ NO_{2}(g)+Cl(g)$

 (ii)  $NO_{2}Cl(g)+Cl(g)$   $\underrightarrow{k_{2}}$   $ NO_{2}(g)+Cl(g)$

 Identify the reacttion intermediate.


A) $NO_{2}Cl(g)$

B) $NO_{2}$

C) $Cl_{2}$

D) Cl(g)

Answer:

Option D

Explanation:

 Cl(g) is the reaction  intermediate involved in the formation of $NO_{2}$ (g) and $Cl_{2}$ (g). Reaction intermediates are those which are formed within the reaction and has no presence in the products. Cl(g) is involved in both the reactions

$ NO_{2}Cl(g) $   $\underrightarrow{k_{1}}$   $ NO_{2}(g)+Cl(g)$

   $NO_{2}Cl(g)+Cl(g)$   $\underrightarrow{k_{2}}$   $ NO_{2}(g)+Cl(g)$