Chemistry | MHT CET 2016 | Discussion Page

In the cell represented by $Pb(s)|Pb^{2+}(1M)||Ag^{+}(1M)|Ag(s).$ the reducing agent is

A) Pb

$Pb^{2+}$

C) Ag

$Ag^{+}$

Option A

In the cell represented by

$Pb(s)|Pb^{2+}(1M)|| Ag^{+}(1M)|Ag(s)$ , the

reducing agent is Pb because it readily gets oxidised to Pb²⁺ and helps in the reduction of $Ag ^{+}$ to Ag(s).

$Pb(s)\rightarrow Pb^{2+}(1M)+2e^{-}$

$Ag^{+}+1e^{-}\rightarrow Ag(s)$

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