Discussion Forum

 In the cell represented by $Pb(s)|Pb^{2+}(1M)||Ag^{+}(1M)|Ag(s).$ the reducing agent is

Answer:

Explanation:

In the cell represented by 

$Pb(s)|Pb^{2+}(1M)|| Ag^{+}(1M)|Ag(s)$  , the

reducing agent is Pb  because it readily gets oxidised to Pb²⁺ and helps in the reduction of $Ag ^{+}$  to Ag(s).

  $Pb(s)\rightarrow Pb^{2+}(1M)+2e^{-}$

$Ag^{+}+1e^{-}\rightarrow  Ag(s)$