Answer:
Option C
Explanation:
$(\frac{\text{d}p}{\text{d}V})_{adiabatic} =\gamma (\frac{\text{d}p}{\text{d}V})_{isothermal}$
List -I
(P) Process I $\Rightarrow$ Adiabatic $\Rightarrow$ Q =0
(Q) Process II $\Rightarrow$ Isobaric
W =pΔV= 3 p0 (3 V0 -V0)= 6 p0 V0
(R) Process III $\Rightarrow$ Isobaric $\Rightarrow$ W=0
(S) Process (IV) $\Rightarrow$ Isothermal $\Rightarrow$Temperature$\Rightarrow$ Constant