Discussion Forum

One mole of a monoatomic ideal gas undergoes four thermodynamic processes as shown schematically in the pV - diagram below. Among these four processes, one is isobaric, one is isochoric , one is isothermal and one is adiabatic. Match the processes mentioned in List -I with the corresponding statements in List -II

Answer:

Explanation:

$(\frac{\text{d}p}{\text{d}V})_{adiabatic} =\gamma (\frac{\text{d}p}{\text{d}V})_{isothermal}$

 List -I

  (P) Process I     $\Rightarrow$   Adiabatic $\Rightarrow$ Q =0

  (Q) Process II  $\Rightarrow$ Isobaric

   W =pΔV= 3 p₀ (3 V₀ -V₀)= 6 p₀ V₀

    (R) Process III $\Rightarrow$ Isobaric $\Rightarrow$ W=0

      (S) Process (IV)  $\Rightarrow$ Isothermal $\Rightarrow$Temperature$\Rightarrow$ Constant