Answer:
Option B
Explanation:
Rate of heat flow will be same.
$\therefore$ $\frac{300-200}{R_{1}}=\frac{200-100}{R_{2}} $
( as $H= \frac{\text{d}Q}{\text{d}t}=\frac{T.D}{R}$)
$\therefore$ $R_{1}=R_{2}\Rightarrow \frac{L_{1}}{K_{1}A_{1}}=\frac{L_{2}}{K_{2}A_{2}}$
$\Rightarrow$ $\frac{K_{1}}{K_{2}}=\frac{A_{2}}{A_{1}}=4$