Answer:
Option A,B,D
Explanation:
(a)At origin, B=0 adue to two wires if l1=l2, hence (Bnet) at origin is equal to B due to ring. which is non-zero.
(b) If l1 >0 and l2 <0, B at origin due to wires will be along $+\hat{k}$ . Direction of B due to ring $-\hat{k}$ direction and hence B can be zero at origin.
(c) If l1< 0 and l2 > 0, B at origin due to wires is along $-\hat{k}$ and also along $-\hat{k}$ due to ring, hence B cannot be zero.
(d)
At centre of ring, B due to wires is along x-axis.
Hence z-component is only because of ring which $B=\frac{\mu_{0}i}{2R}(-\hat{k})$