Answer:
Option (A,C)
Explanation:
$h=\frac{2\sigma\cos\theta}{r\rho g}$
$(a) \rightarrow h\alpha\frac{1}{r}$
(b) h depends upon $\sigma$
(c) If lift is going up with constant acceleration
$g_{eff}= (g+a)\Rightarrow h= \frac{2\sigma \cos\theta}{r\rho (g+a)}$
It means h decreases.
(d) h is proportional $\cos\theta$