Discussion Forum

1)

A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 10¹² per second. What is the force constant of the bonds connecting one atom with other? ( Take, molecular weight of silver=108 and Avogadro  number=6.02×10²³ g mol^-1)

 

Answer:

Option A

Explanation:

 For a harmonic oscillator.

$T=2\pi \sqrt{\frac{m}{k}}$ , where k= force constant and

$T=\frac{1}{f}$

$\therefore$      $k =4\pi^{2}f^{2}m$

$=4\times (\frac{22}{7})^{2}\times (10^{12})^{2}\times \frac{108 \times 10^{-3}}{6.02\times 10^{23}}$

$\Rightarrow$        k=7.1 N/m