Answer:
Option A,D
Explanation:
It is given that T is tangents to S1 at P and S2 at Q and S1 and S2 touch externally at M.
$\therefore$ MN=NP=NQ
$\therefore$ Locus of M is a circle having PQ as its diameter of circle.
$\therefore$ Equation of circle, (x-2)(x+2) + (y+5)(y-7)=0
$\Rightarrow$ x2 +y2-2y-39=0
Hence, E1 : x2 +y2 -2y-39=0, x≠ ± 2
Locus of mid-point of chord (h,k) of the circle E1 is xh+yk-(y+k)-39 = h2 +k2 -2k-39
$\Rightarrow$ xh+yk-y-k=h2 +k2 -2k
Since the chord is passing through (1,1)
Locus of midpoint of the chord (h,k) is
h+k-1-k= h2 +k2 -2k
$\Rightarrow$ h2 +k2-2k-h+1=0
Locus is E2 : x2 +y2 -x-2y+1=0
Now, after checking options , (a) and (d) are correct.