1) The value of ((log29)2)1log2(log29)×1(√7)log47 is............ A) 6 B) 8 C) 10 D) 4 Answer: Option BExplanation:((log29)2)1log2(log29)×1(√7)log47 = (log29)2log2log29×712log74 = (log29)loglog2922×7log72 = 22× 2=8