Answer:
Option A
Explanation:
Given 6 different novels and 3 different dictionaries.
Number of ways of selecting 4 novels from 6 novel is $^{6}C_{4}=\frac{6!}{2!4!}=15$
Number of ways of selecting 1 dictionary is from 3 dictionaries is $^{3}C_{1}=\frac{3!}{1!2!}=3$
$\therefore$ Total number of arrangement of 4 novels and 1 dictionary where dictionary is always in the middle is
$15\times 3\times 4!=45\times 24=1080$
