Answer:
Option D
Explanation:
The equations of chemical reactions occurring during the process are-
In the presence of oxygen
$2PbS+3O_{2}\rightarrow 2PbO+2SO_{2}.....(i)$
By self reduction
$2PbO+PbS_{}\rightarrow 3Pb+SO_{2}$
Thus 3 moles of 02 produces 3 moles of Pb
i.e.,
32 × 3=96 g of O2 produces
3 × 207 =621 g of Pb
So 1000 g (1kg) of oxygen will produce $\frac{621}{96}\times 1000= 646815 g$
= 6.4687 kg = 6.47 kg
Alternatively
From the direct equation,
$Pb S+O_{2}\rightarrow Pb +SO_{2}$
32g 207g
So, 32g of O2 gives 207 g of Pb
1 g of O2 will give $\frac{207}{32}$ g of Pb
1000g of O2 will give $\frac{207}{32}\times 1000$
= 6468.75g= 6.46875 kg
=6.47 kg