Answer:
Option C
Explanation:
Let the oxidation state of Cr in all cases is 'x'
(i) Oxidation state of Cr in [Cr(H2O)6 ]Cl3
x + (0 × 6) + (-1 × 3)=0
or x+0-3=0
or x= +3
(ii) Oxidation state of Cr in [Cr(C6H6)2]
x+(2× 0)=0
or x=0
(iii) Oxidation state of Cr in
K2[Cr (CN)2(O)2 (O2 )(NH3)]
1×2+x+ (-1× 2) + (-2× 2) + (-2)+0=0
or 2 +x-2-4-2=0
or x-6=0
hence x=+6
Thus, +3,0 and +6 is the answer