1) The area ( in sq units) of the region {(x,y):x ≥ 0, x +y ≤ 3, x2 ≤ 4y and y ≤ 1+√x } is A) 5912 B) 32 C) 73 D) 52 Answer: Option DExplanation:Required area =∫10(1+√x)dx+∫21(3−x)dx−∫20x24dx = =[x+x323/2]10+[3x−x22]21−[x312]20 =(1+23)+(6−2−3+12)−(812) =53+32−23=1+32=52sq.units