1)

The major products obtained in the following reaction is 

  7112019577_react.PNG


A) $(\pm)C_{6}H_{5}CH(O^{t}Bu)CH_{2}C_{6}H_{5}$

B) $C_{6}H_{5}CH= CHC_{6}H_{5}$

C) $(+)C_{6}H_{5}CH(O^{t}Bu)CH_{2}C_{6}H_{5}$

D) $(-)C_{6}H_{5}CH(O^{t}Bu)CH_{2}C_{6}H_{5}$

Answer:

Option B

Explanation:

An alkyl halide in the presence of a bulkier base removes a proton from a carbon adjacent to the carbon bonded to the halogen. This reaction is called E2 ( $\beta$ -elimination reaction)

7112019169_reaaa.PNG