1) The major products obtained in the following reaction is A) $(\pm)C_{6}H_{5}CH(O^{t}Bu)CH_{2}C_{6}H_{5}$ B) $C_{6}H_{5}CH= CHC_{6}H_{5}$ C) $(+)C_{6}H_{5}CH(O^{t}Bu)CH_{2}C_{6}H_{5}$ D) $(-)C_{6}H_{5}CH(O^{t}Bu)CH_{2}C_{6}H_{5}$ Answer: Option BExplanation:An alkyl halide in the presence of a bulkier base removes a proton from a carbon adjacent to the carbon bonded to the halogen. This reaction is called E2 ( $\beta$ -elimination reaction)