Answer:
Option B
Explanation:
Induced constant . $I= \frac{e}{R}$
Here, e= induced emf
$= \frac{d\phi}{dt}$
$I=\frac{e}{R}= (\frac{d\phi}{dt}).\frac{1}{R}$
$d\phi=IRdt$
$\phi =\int_{}^{} IRdt$
$\therefore$ Here, R is constant
$\therefore$ $\phi =R\int_{}^{} Idt$
$\int_{}^{} I.dt =$ Area under I- t graph
= $\frac{1}{2}\times 10 \times 0.5 =2.5$
$\therefore$ $\phi =R\times 25$
= 100 × 2.5
=250 Wb