Discussion Forum

A copper ball of mass 100 g is at a temperature T. It is dropped in a copper calorimeter of mass 100g, filled with 170 g of water at room temperature. Subsequently, the temperature  of the system is found to be 75° C . T is (Given, room temperature = 30° C, the specific heat of copper =0.1 cal/ g° C )

Answer:

Explanation:

Heat gained (water+calorimeter) = Heat lost by copper ball

  $\Rightarrow  m_{w}s_{w}\triangle T+m_{c}s_{c}\triangle T =m_{B}s_{B}\triangle T$

$\Rightarrow  170\times 1 \times(75-30) +100\times 0.1 \times (75-30)$

$=100\times 0.1\times (T-75)$

$\therefore$      T = 885° C