Answer:
Option C
Explanation:
We have $\lambda =\frac{hc}{\triangle E}$
So ratio of wavelengths
$\frac{\lambda_{1}}{\lambda_{2}}=\frac{hc/\triangle E_{1}}{hc/\triangle E_{2}}=\frac{\triangle E_{2}}{\triangle E_{1}}= \frac{(\frac{4}{3}E-E)}{2E-E}=\frac{1}{3}$