1)

Some energy levels of molecule are shown in the figure. The ratio of the wavelengths r= λ12 is given by 

                1610201975_vvvv.JPG


A) $r=\frac{2}{3}$

B) $r=\frac{3}{4}$

C) $r=\frac{1}{3}$

D) $r=\frac{4}{3}$

Answer:

Option C

Explanation:

We have   $\lambda =\frac{hc}{\triangle E}$

        So ratio of wavelengths

$\frac{\lambda_{1}}{\lambda_{2}}=\frac{hc/\triangle E_{1}}{hc/\triangle E_{2}}=\frac{\triangle E_{2}}{\triangle E_{1}}= \frac{(\frac{4}{3}E-E)}{2E-E}=\frac{1}{3}$