Discussion Forum



1)

The order of the oxidation state of the phosphorous atom in H3PO2 , H3PO4 , H3PO3  and H4P2O6 is


A) $H_{3}PO_{4}>H_{3}PO_{2}>H_{3}PO_{3}>H_{4}P_{2}O_{6}$

B) $H_{3}PO_{4}>H_{4}P_{2}O_{6}>H_{3}PO_{3}>H_{3}P_{}O_{2}$

C) $H_{3}PO_{2}>H_{3}P_{}O_{3}>H_{4}P_{2}O_{6}>H_{3}P_{}O_{4}$

D) $H_{3}PO_{3}>H_{3}P_{}O_{2}>H_{3}P_{}O_{4}>H_{4}P_{2}O_{6}$

Answer:

Option B

Explanation:

$H_{3}P^{6+}O_{4}>H_{4}P_2^{+4}O_{6}>H_{3}P^{+3}O_{3}>H_{3}P^{+1}O_{2}$