1) The order of the oxidation state of the phosphorous atom in H3PO2 , H3PO4 , H3PO3 and H4P2O6 is A) $H_{3}PO_{4}>H_{3}PO_{2}>H_{3}PO_{3}>H_{4}P_{2}O_{6}$ B) $H_{3}PO_{4}>H_{4}P_{2}O_{6}>H_{3}PO_{3}>H_{3}P_{}O_{2}$ C) $H_{3}PO_{2}>H_{3}P_{}O_{3}>H_{4}P_{2}O_{6}>H_{3}P_{}O_{4}$ D) $H_{3}PO_{3}>H_{3}P_{}O_{2}>H_{3}P_{}O_{4}>H_{4}P_{2}O_{6}$ Answer: Option BExplanation:$H_{3}P^{6+}O_{4}>H_{4}P_2^{+4}O_{6}>H_{3}P^{+3}O_{3}>H_{3}P^{+1}O_{2}$
