1) The equation of the plane passing through the point(1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7 A) 14x+2y-15z=1 B) -14x+2y+15z=3 C) 14x-2y+15z=27 D) 14x+2y+15z=31 Answer: Option DExplanation:Let the equation of plane be ax+by+cz=1, Then a+b+c=1 2a+b-2c=0 3a-6b-2c=0 $\Rightarrow$ a=7b $c=\frac{15b}{2}$ $b=\frac{2}{31}$ ,$a=\frac{14}{31}$, $c=\frac{15}{31}$ 14x+2y+15z=31
