Discussion Forum

The equation of the plane passing through the point(1,1,1) and perpendicular to the planes

2x+y-2z=5 and 3x-6y-2z=7

Answer:

Explanation:

Let the equation of plane be ax+by+cz=1, Then

 a+b+c=1

2a+b-2c=0

3a-6b-2c=0

$\Rightarrow$      a=7b

   $c=\frac{15b}{2}$

$b=\frac{2}{31}$ ,$a=\frac{14}{31}$, $c=\frac{15}{31}$

14x+2y+15z=31