Answer:
Option A,C
Explanation:
(a) If force is applied normal to surface at P, then the line of action of force will pass from Q and thus $\tau$ =0
(b) wheel can climb
(c) $\tau=F(2R\cos\theta)-mgR\cos\theta$
$\tau\propto\cos\theta$
Hence, as θ increases, $\tau$ decreases so it correct
(d)
$ \tau =Fr_{\perp}-mg\cos\theta:\tau$ increases with θ