Answer:
Option B,C,D OR D
Explanation:
Assumption e=1
[black body radiation]
P=σA(T4−T40)
(c) Prad=σAT2=σ.1.(T0+10)4
= σT40(1+10T0)4
[T0 = 300 Kg given]
= σ.(300)4(1+40300)=460×1715=520J
Pnet= 520-460=60W
⇒ energy radiated in 1 s=60J
(b) P= σA(T4−T40)
dP=σA(0−4T30dT)
and dT=−△T
⇒ dP=4σAT30△T
(d) If the surface area decreases, then energy radiation also decreases
Note: While giving answers b and c it is assumed that energy radiated refers to the net radiation. If energy radiated is taken as the only emission then b and c will not be included in the answer