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In the Hofmann-bromamide degradation reaction, the number of moles of NaOH and Br₂used Per mole of amine produce are

A) 4 moles of NaOH and 2 moles of

$Br_{2}$

B) 2 moles of NaOH and 2 moles of

$Br_{2}$

C) 4 moles of NaOH and 1 mole of

$Br_{2}$

D) 1 mole of NaOH and 1 mole of

$Br_{2}$

Option C

Hofmann-bromamide degradation reaction is given as:

$RCONH_{2}$ + $4NaOH$ + $Br_{2}$ $\rightarrow$ $RNH_{2}$ + $Na_{2}CO_{3}$ + $2NaBr$ + $2H_{2}O$

Hence, four moles of NaOH and one mole of are used.

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