1)

Decomposition of H2O follows a first-order reaction. In 50 min, the concentration of H2O2 - decreases from 0.5 to 0.25 in one such decomposition. When the concentration of H2O  reaches 0.05  M, the rate of formation of O2 will be 


A) 6.93×104mol min1

B) 2.66L/minat STP

C) 1.34×102mol min1

D) 6.93×102mol min1

Answer:

Option A

Explanation:

For the first-order reaction,

k=2.303tlogaax

Given, t= 50min  a= 0.5 M

a-x= 0.125 M

Therefore,

k=2.30350log0.50.125=0.0277min1

Now, as per reaction

2H2O22H2O+O2

12d[H2O2]dt=12d[H2O]dt=d[O2]dt

Rate of reaction 

d[H2O2]dt=k[H2O2]

Therefore,

d[O2]dt=12dH2O2dt=12k[H2O2]....(i)

When concentration of of H2O2 reaches  0.05 M 

d[O2]dt=12×.0277×.05

or  d[O2]dt=6.93×104mol min1