Answer:
Option A
Explanation:
For the first-order reaction,
k=2.303tlogaa−x
Given, t= 50min a= 0.5 M
a-x= 0.125 M
Therefore,
k=2.30350log0.50.125=0.0277min−1
Now, as per reaction
2H2O2→2H2O+O2
−12d[H2O2]dt=12d[H2O]dt=d[O2]dt
Rate of reaction
−d[H2O2]dt=k[H2O2]
Therefore,
−d[O2]dt=12dH2O2dt=12k[H2O2]....(i)
When concentration of of H2O2 reaches 0.05 M
d[O2]dt=12×.0277×.05
or d[O2]dt=6.93×10−4mol min−1