1)

2-chloro-2-rnethylpentane on reaction with sodium methoxide in methanol yields

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A) Both I and III

B) Only III

C) Both I and II

D) All of these

Answer:

Option D

Explanation:

Key concept Strong nucleophile

$(\overline{O}Me)$ in polar solvent $(MeOH)$ gives elimination products over substitution products but all products are possible in different yields.

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