Answer:
Option C
Explanation:
We have , $\frac{2b^{2}}{a}=8$ and 2b=ae
$\Rightarrow b^{2}=4a$ and 2b=ae
consider 2b=ae
$\Rightarrow 4b^{2}=a^{2}e^{2}$
$\Rightarrow 4a^{2}(e^{2}-1)=a^{2}e^{2}$
$\Rightarrow 4e^{2}-4=e^{2} [\therefore a\neq 0]$
$\Rightarrow 3e^{2}=4$
$\Rightarrow e=\frac{2}{\sqrt{3}} [\because e>0]$
