Loading [MathJax]/jax/output/HTML-CSS/jax.js


1)

A pendulum clock loses  12 s a day if the temperature is 40° C and gains 4 s a day if the temperature is 20° C. The temperature at which the clock will show the correct time and the coefficient of linear expansion α of the metal of the pendulum shaft are, respectively


A) 25oC,α=1.85×105/oC

B) 60oC,α=1.85×104/oC

C) 30oC,α=1.85×103/oC

D) 55oC,α=1.85×102/oC

Answer:

Option A

Explanation:

T0=2πLg

T=T0+T=2πL+Lg

T=T0+T=2πL(1+θ)g

={2πLg}(1+αθ)12=T0(1+αθ2)

       T=TT0=αθT02

T1T2=αθ1T0αθ2T0

   124=400θθ200

   3(θ200)=400θ

     4θ=1000

     θ=250C

 Time gained or lost given by

    T=(TT0+T)t=tT0t

From Eq.(i0.

   TT0=αθ2

t=α(θ)t2

 

12=α(400250)(24×3600)2

α=1.85×105/0C