Answer:
Option A,C.D
Explanation:
$Na_{2}B_{4}O_{7}.10H_{2}O$ (borax) is actually made of two tetrahedral and two triangular units and is actually written as
$Na_{2}[B_{4}O_{5}(OH)_{4}].5H_{2}O$
(a) Thus, correct
(b) Boron atoms are in different planes thus, incorrect
(c) Two $sp^{2}$ and two $sp^{3}$ - hybridised B atoms thus, correct
(d) Each boron has one- OH group thus, correct