Answer:
Option C
Explanation:
Only -CHO group is to be reduced to -CH2OH
It can be done using NaBH4 in C2H5OH

(a)LiAlH4/(C2H5)2O reduces I,II and III into - CH2OH , and IV into diol.
(b) BH3 / THF show same properties as (a)
(c) NaBH4 / C2H5OH reduces III into -CH2OH
(d) Raney nickel, same as (a) and (b) thus (c) is correct reagent