Answer:
Option C
Explanation:
Using the relation
$R=R_{0}\left(\frac{1}{2}\right)^{n}$
Here. R is activity of radioactive substance, R0 initial activity and n is number of half-lives.
$1=64\left(\frac{1}{2}^{}\right)^{n}$
Solving we get, n=6
Now ,t =n(t1\2)=6(18 days)=108 days