1)

 A hydrogen atom in its ground state is irradiated by light of wavelength 970Å. Taking hc/e=1.237×106eVm and the ground state energy of hydrogen atom as - 13.6 eV the number of lines present in the emission spectrum is


A) 3

B) 6

C) 2

D) 4`

Answer:

Option B

Explanation:

Energy of incident light (in eV) E=12375970=12.7eV

After excitation, let the electron jumps to nth State ,then 13.6n2=13.6+12.7

Solving this equation, we get n=4;

Total number of lines in emission spectrum ,=n(n1)2=4(41)2=6