Answer:
Option A
Explanation:
According to the given information.
the figure should be as follows.
Let the height of tower =h

In △EDA,
tan300=EDAD
1√3=EDAD=hAD
⇒ AD=h√3
In △EDB,
tan450=hBD⇒BD=h
△EDC
tan600=hCD⇒CD=h√3
Now, ABBC=AD−BDBD−CD
⇒ ABBC=h√3−hh−h√3
⇒ ABBC=h(√3−1)h(√3−1)√3
⇒ ABBC=(√3−1)(√3−1)×√3
⇒ ABBC=√31
∴ AB:BC= √3:1