Discussion Forum



1)

 In the following sequence  of reaction,

  Toluene   

 $\underrightarrow{KmnO_{4}} $   A   $\underrightarrow{SOCl_{2}} $  B    $\xrightarrow [ {BasO_{4}}]{{H_{2}/Pd}}$  C

 The product  C is


A) $C_{6}H_{5}COOH$

B) $C_{6}H_{5}CH_{3}$

C) $C_{6}H_{5}CH_{2}OH$

D) $C_{6}H_{5}CHO$

Answer:

Option D

Explanation:

Toluene undergoes oxidation with $KMnO_{4}$, forms benzoic acid. In this conversion, alkyl part of toluene converts into carboxylic group. Further, benzoic acid  reacts with thionyl chloride ( SOCl2 ) to give  benzoyl chloride  which upon reduction  with  $H_{2}/Pd$   or  $BaSO_{4}$   forms benzaldehyde (Rosenmund Reduction)

          The conversion looks like,

132021222_m46.JPG