1)

Which of the following  compound will exhibit  geometrical isomerism?


A) 1-phenyl-2-butene

B) 3-phenyl-1-butene

C) 2-phenyl-1-butene

D) 1,1- diphenyl-1-propane

Answer:

Option A

Explanation:

Alkene in which different groups are attached with the double-bonded carbon atoms, exhibit geometrical isomerism.

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It will show geometrical isomerism,

132021282_m45.JPG

1,1- diphenyl-1- propane being an alkane  (saturated compound) does not show geometrical isomerism.

 Time Saving Technique.

                We do not need the check all options, but it should remind that double-bonded compounds show geometrical isomerism. Thus (d) is eliminated, (i.e, propane). Now, eliminate the terminal alkene and get the correct response.