Answer:
Option B
Explanation:
Given, Q=2F
Atomic mass of Cu= 63.5 u
Valancy of the metal Z= 2
we have, $CuSo_{4}\rightarrow Cu^{2+}+SO_{4}^{2-}$
$ Cu^{2+}+2e^{-}\rightarrow Cu$
1 mol 2 mol 1 mol=63.5 g
2F
Alternatively, W= ZQ
= $\frac{E}{F}.2F=2E$
= $\frac{2\times 63.5}{2}=63.5$
