Answer:
Option C
Explanation:
Central Idea Frequency associated with AM are $f_{c}-f_{m},f,f_{c}+f_{m}$
According to the question
$f_{c}=2MHz=2000kHz$
$f_{m}=5kHz$
Thus, frequency of the resultant signal is/are carrier frequency $f_{c}$ = 2000kHz,
LSB frequency $f_{c}-f_{m}$=2000kHz-5kHz=1995 kHz and USB Freequency $f_{c}+f_{m}$=2005kHz