Answer:
Option B
Explanation:
We can write receiving angle of nacked eye as
$\theta=1.22\frac{\lambda}{D}$
Where, D is the diameter of eye lens.
or $\frac{Y}{25\times10^{-2}}=\frac{1.22\times500\times 10^{-9}}{0.25\times2\times 10^{-2}}$
$Y=30\times 10^{-6}m=30\mu m$