Answer:
Option C
Explanation:
Since B is uniform only torque acts on a current-carrying loop.
As, $\tau=M\times B$
$\Rightarrow$ $|\tau|=|M||B|\sin\theta$
For orientation shown in (b) $\theta=0^{0},\tau=0$
(stable equilibirum)
and for (d) $\theta=\pi,\tau=0$ (unstable equilibium)