Answer:
Option A
Explanation:
Let C JK-1 be the heat energy capacity of the calorimeter.
Maa of solution
=200mL×1gmL−1=200g
Heat evolved in Exp.I
= 57×1000×0.1(mol)=5700J
⇒5700J=(200×4.2+C)×5.7
⇒100=200×4.2+C ......(i)
Let x kJ/mol is heat evolved in neutralisation of acetic acid.
⇒x×1000×0.10=(200×4.2+C)×5.6
⇒x×1005.6=200×4.2+C ...........(ii)
From (i) and (ii): x=56 kJ/mol
⇒ Enthalpy of ionisation of acetic acid
= -56-(-57)= 1 kJ/MOL