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The pair(s) of ions where both the ions are precipitated upon passing H₂S gas in presence of dilute HCl, is (are)

$Ba^{2+},Zn^{2+}$

$Bi^{3+},Fe^{3+}$

$Cu^{2+},Pb^{2+}$

$Hg^{2+},Bi^{3+}$

Option C,D

Only radicals of I and II group of qualitative analysis get precipitated with H₂S in the presence of dilute HCL

Black

$Pb^{2+}+H_{2} S$ $\underrightarrow{H^{+}}$ $PbS\downarrow$

Black

(d) $Hg^{2+}+H_{2} S$ $\underrightarrow{H^{+}}$ $HgS\downarrow$

Black
$Bi^{3+}+H_{2} S$ $\underrightarrow{H^{+}}$ $Bi_{2}S_{3}$ $\downarrow$

Brown ppt

Ba²⁺ , Zn²⁺ and Fe³⁺ are not precipitated as sulphide.

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