Discussion Forum

In dilute aqueous H₂SO_4, the complex diaquadioxalatoferrate (II) is oxidised by MnO₄^-. For this reaction, the ratio of the rate of change [H⁺] to the rate of change of [MnO₄^-]  is 

Answer:

Explanation:

The balanced redox reaction is

                  $MnO_{4}^{-}+[Fe(H_{2}O)_{2}(C_{2}O_{4})_{2}]^{2-}+8H^{+}\rightarrow Mn^{2+}+Fe^{3+}+4CO_{2}+6H_{2}O$

$\Rightarrow$                                $\frac{r[H^{+}]}{r[MnO_{4}^{-}]}=\frac{8}{1}=8$