1)

 Three moles of B2H6 are completely reacted with methanol. The number of moles of boron containing product formed is 


A) 4

B) 2

C) 5

D) 6

Answer:

Option D

Explanation:

$B_{2}H_{6}+6CH_{3}OH\rightarrow2[B(OCH_{3})_{3}]+6H_{2}$ .Therefore , from 3 moles of B2H6 . 6 moles  of   $B(OCH_{3})_{3}$   will be