1) Three moles of B2H6 are completely reacted with methanol. The number of moles of boron containing product formed is A) 4 B) 2 C) 5 D) 6 Answer: Option DExplanation:$B_{2}H_{6}+6CH_{3}OH\rightarrow2[B(OCH_{3})_{3}]+6H_{2}$ .Therefore , from 3 moles of B2H6 . 6 moles of $B(OCH_{3})_{3}$ will be