Answer:
Option C
Explanation:
Let initial power available from the plant is P0 . After time t=nT or n half livers , this will become
$\left(\frac{1}{2}\right)^{n}P_{0}$ , Now , it is given that,
$\left(\frac{1}{2}\right)^{n}P_{0}=12.5$ % of $P_{0}=(0.125)P_{0}$
Solving this equation we get ,
n=3