Answer:
Option D
Explanation:
Let a,ar, ar2 are in GP (r>1)
On multiplying middle team by 2, a, 2ar, ar2 are in AP.
$\Rightarrow$ $4ar=a+ar^{2}$
$\Rightarrow$ $r^{2}-4r+1=0$
$\Rightarrow$ $r=\frac{4\pm\sqrt{16-4}}{2}= 2\pm\sqrt{3}$
$\Rightarrow$ $r=2+\sqrt{3}$ [ $\because$ AP is increasing ]