Discussion Forum

 The ratio of masses of oxygen and nitrogen of a  particular gaseous mixture is 1:4. The ratio of the number of  their molecule is 

Answer:

Explanation:

$\frac{n_{O_{2}}}{n_{N_{2}}}=\frac{\frac{(m_{O_{2})}}{(M_{O_{2}})}}{\frac{(m_{N_{2}})}{(M_{N_{2}})}}$

where, 

  $m_{O_{2}}=$   given mass of O₂

 $m_{N_{2}}=$  given mass of N₂

 $M_{O_{2}}=$   molecular mass of O₂

 $M_{N_{2}}=$      molecular mass of N₂

 $n_{O_{2}}=$    number of moles O₂

 $n_{N_{2}}=$   number of moles N₂

            $=\left[\frac{m_{O_{2}}}{m_{N_{2}}}\right]\frac{28}{32}=\frac{1}{4}\times\frac{28}{32}=\frac{7}{32}$