Answer:
Option B
Explanation:
Higher the position of element in the electrochemical series more difficult is the reduction of its cations.
If Ca2+ (aq) is electrolysed, water is reduced in preference to it. Hence, it cannot be reduced electrolytically from its aqueous solution
$Ca^{2+}(aq)+H_{2}O\rightarrow Ca^{2+}+OH^{-}+H_{2}\uparrow$